Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Number of prime numbers satisfying the inequality 
is equal to
Text Solution
Verified by ExpertsThe correct answer is:
A
log 3 
⇒ |x 2 – 4x| + 3 ≥ x 2 + |x – 5|
Case-I x ≥ 5 x 2 – 4x + 3 ≥ x 2 + x – 5 ⇒ –5x + 8 ≥ 0
⇒ x ≤ 
(No solution)
Case-II x ∈ (– ∞ , 0] ∪ [4, 5]
x 2 – 4x + 3 ≥ x 2 + x – 5 ⇒ – 3x ≥ 2 ⇒ x ≤ 
Case-III x ∈ [0, 4]
4x – x 2 + 3 ≥ x 2 – x + 5 ⇒ 2x 2 – 5x + 2 ≤ 0 ⇒ x ∈ 
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